Question
Calculate the amount of urea for 4000 m2 area
if nitrogen application rate is 120 kg/haSolution
= 120/46*100= 260.87 kg/ha For 10,000 m2, amount of urea applied=260.87 kg/ha For 4000m2,amount of urea will be=260.87/10,000*4000= 104.348 kg
(√7225 x √1225)/(√625) = ?
(? + 16) × 12 + 25% of 840 = 252 + 5
81% of 2300 – 34% of 550 = ?
Find the value of ‘x’ if (5 × 196 – 340 ÷ 17) ÷ 20 = √1600 – x.
6 × 1.8 × 0.25 × 70 = ? + 9.5
- What will come in place of (?), in the given expression.
(81 ÷ 9) + (121 ÷ 11) + (64 ÷ 8) = ? What will come in the place of question mark (?) in the given expression?
{180 + (2250/15)} ÷ 11 = ?2 + 14
72 x 60 x 22 x 32 =?
What will come in the place of question mark (?) in the given expression?
(28/14) of 56 + ? = 920 ÷ 5
2/5 of 3/4 of 7/9 of 7200 = ?