Question
Calculate the amount of urea for 4000 m2 area
if nitrogen application rate is 120 kg/haSolution
= 120/46*100= 260.87 kg/ha For 10,000 m2, amount of urea applied=260.87 kg/ha For 4000m2,amount of urea will be=260.87/10,000*4000= 104.348 kg
What is the value of 143 + 163 + 183 + … + 303?
Find the simplified value of the following expression:
14.25 × 32 – 11.4 × 15 + 8 – 712 ÷ 8 + 34.15 × 20 – 27 × 21 = ?
...√4761 ÷ 23 + √12769 = ? × 58
(2 ÷ 3) × (4 ÷ 12) × (? ÷ 10) × 45 × (1 ÷ 5) = (? ÷ 6) + (2 ÷ 5)
- If (6 × 225 – 432 ÷ 18) ÷ 24 = √2025 – x, what is the value of ‘x’?
√? = 120 - 102 + ∛125
4567.89 - 567.89 - 678.89 = ?
36% of 250 + 26 ÷ 2 × ? = 207
The speed of the stream is 10 km/h. Boat ‘A’ covers 110 km distance against the stream in 11 hours and boat ‘B’ covers 65 km distance against th...
9999² + 1111² =?