In India for hybrid seed production in maize we use:

(5³ + 480 ÷ 4)% of 20 = ?% of 70

567-4824 ÷ 134 =? × 9

68% of 450 – 1008 ÷ 14 + 516 ÷ 43 =?

690 ÷ (75% of 460) = ? ÷ (50% of 160)

The sum of two numbers is 16 and their product is 63. The sum of their reciprocal is equal to:

√2401 × (√2116 ÷ 23) × 21 ÷ 3 = ?

(320 + 342 + 530 + 915) ÷ (20 + 22 – x + 18) = 43, then the value of x is:

7(3/6) of 534 + 262 = 61800 - ?

84% of 800 + 70% of 640 = 14 × ?

`sqrt(7744)`   - `sqrt(4761)` + `sqrt(8281)`  + `sqrt(5625)` + ? = 1856