The synthesis of ATP via electron flow through the ETS, with oxygen as the terminal electron acceptor, is known as oxidative phosphorylation.
√2401 × (√2116 ÷ 23) × 21 ÷ 3 = ?
(3984 ÷ 24) x (5862 ÷ 40) = ?
40% are the passing marks. A student gets 250 marks yet fails by 38 marks. What is the maximum marks?
The value of ((0.27)2-(0.13)2) / (0.27 + 0.13) is:
Find the HCF of 15x2 + 8x – 12, 3x² + x – 2, 3x² - 2x, 9x² - 12x + 4
7(3/6) of 534 + 262 = 61800 - ?
Find the simplified value of the given expression:
224 ÷ 4 + 7 X 36 - 8 of 15 + 162 - 300
?% of 24% of 1200 + 12 × 11 = 204
( 12.43×12.43×12.43 +19.57×19.57×19.57) / (12.43×12.43-12.43×19.57 +19.57×19.57)
30% of 600 –
/Quantitative_Aptitude/Simplification/233374...</a></li> <div class=)
