If CLR of milk is 28, then the specific gravity of milk will be-
Specific Gravity = CLR / 1000 + 1 Given that CLR of milk is 28, we can calculate the specific gravity as follows: Specific Gravity = 28 / 1000 + 1 = 0.028 + 1 = 1.028
I. 6x² + 37x + 45 = 0
II. 3y² - 11y + 6 = 0
I. x² - 19x + 84 = 0
II. y² - 25y + 156 = 0
I. 4 x ² - 4 x + 1 = 0
II. 4 y ² + 4 y + 1 = 0
...I. 8x2- 2x – 15 = 0
II. 12y2- 17y – 40 = 0
I. 3y² - 20y + 25 = 0
II. 3x² - 8x + 5 = 0
I. 2(x+2)+ 2(-x)=5
II. (1/(y+1)+ 1/(y+5))=(1/(y+2)+ 1/(y+4))
I. 2x2 - 9 x + 9 = 0
II. 2y2 - 7 y + 3 = 0
I. x2 - 9x - 52 = 0
II. y2 - 16y + 63 = 0
I. 15b2+ 26b + 8 = 0
II. 20a2+ 7a - 6 = 0
I. 12x2 + 22x + 8 = 0
II. 4y2 - y − 3 = 0
