An area of 0.6 ha each of wheat and maize is irrigated daily with a discharge of 2000 litre per minute for a period of 15 hours. Each crop receives 8 cm of water. Determine efficiency (%) of irrigation system
Irrigation efficiency = water that reached the field/ total water delivered × 100 Total field area = 0.6 + 0.6 ha = 1.2 ha Depth of water = 8 cm Total volume of water reached the field = 1.2 × 10,000 × 0.08 = 960 m3 1 m3 = 1000l 960 m3 = 9,60,000 l Total water delivered in the field = 2000 × 60× 15 l Irrigation efficiency = 9,60,000 l / 2000 × 60× 15 l = 53.3 %
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