Question
While conducting a chi-square test to examine the
independence of attributes in an m x n contingency table, what formula determines the degree of freedom?Solution
In a contingency table with m rows and n columns, the degrees of freedom for a chi-square test to determine independence is calculated as (m-1)(n-1). This accounts for the number of categories minus one in each dimension, allowing for the calculation of expected frequencies under the assumption of independence.
If x2a = y2b =z2c ≠ 0 and x2 = yz, then the value of (ab + bc + ca) /bc is :
If p = 28 - q - r and pq + r(q + p) = 182, then find the value of (p² + q² + r²).
If a, b and c are integers such that a 2 Â + b 2 Â + c 2Â = 228, a + b + c = 26 and b = c, then find the value of a?
If x = 15, find x5 - 16x4 + 16x3 - 16x2 + 16x - 16 = ?
Find the value of ‘x’ in the given expression:
(49/16)x × (64/343)x-1 = 4/7
If 9 : 12 :: 12: x, and 28: 42:: 42: y, then the value of 2x + y is:Â
If x = 15
find x 5 - 16 x 4 + 16 x 3 - 16 x 2 + 16 x  - 16 = ?
- If (m + n + o) = 16 and (mn + no + om) = 80, then find the value of (m² + n² + o²).
- Find the remainder on dividing (5x 3  + 4x 2  – 10x + 1) by (2x – 4).
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