To determine the optimum run size for bearing manufacture, we can use the Economic Order Quantity (EOQ) formula. The EOQ formula is given by: EOQ = √((2 * D * S) / H) Where: D = Annual demand (units) S = Set-up cost per run H = Inventory holding cost per unit per time period Given: Annual demand (D) = 24,000 bearings per annum Set-up cost per run (S) = Rs. 324 Inventory holding cost per bearing per month (H) = 10 paise = 0.10 rupees First, let's convert the holding cost to rupees per year: Holding cost per bearing per year = 0.10 rupees * 12 months = Rs. 1.20 Now, we can plug the values into the EOQ formula: EOQ = √((2 * 24,000 * 324) / 1.20) EOQ = √(15552000 / 1.20) EOQ = √12960000 EOQ ≈ 3,600 bearings (rounded off to the nearest whole number) Therefore, the optimum run size for bearing manufacture would be 3600 bearings. So, the correct option is: 3600.
1111.25 × 9.05 + 2323.23 × 9.05 – 2121.37 × 9.05 = ?
Find the difference of day had the highest number of books and that of lowest number of books sold?
25.19% of (?2 ÷ 38.87 × 4679.94) = 6299.82 ÷ 419.78 × 50.15
? × 32.91 – 847.95 ÷ √16.4 – 13.982 = √24.7 × 24.04
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
11.11% of 1800.89 + 34.89 X 10.99 - 500.50 = ?
Solve the following expression and calculate the approximate value.
802 of
24.89% of 720.01 - 4.09 × ? = (5.89)2
(363.89% of 224.98 – 319.86% of 134.94) ÷ ? = √(134.88 ÷ 15.25)