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From statement I: Relative speed = 9x + 5x = 14x units Sum of Length of buses = 1400 metre Required time = 1400/(14 x) = no result From statement II: Let length of bus A = y Speed of Bus A = y/15 = (y + 750 )/20 ⇒ 20 y = 15 y + 11250 ⇒ 5 y = 11250 ⇒ y = 2,250 = length of bus A Now we can’t find answer by only one statement & if we use both, it will contradict each other because in 1st statement, sum of length of two buses is 1400 & in 2nd statement, length of bus A only is 2250 So we cant find answer by even using both statements.
Find the approximate value of Question mark(?) for given equation.
(71.92% of 149.99) ÷ 12.04 + 107.98 = ?
12.99% of 499.99 ÷ 13.17 = ? ÷ 20.15
(2310.23 ÷ 32.98) + (1008.32 ÷ 23.9) + 1594.11 = ?
?% of 549.83 – 18.05 × 31.96 = 44.94% of 479.84 – 13.98 × 33.13
19.87% of (49.68 × ?) = 19.78% of 1099.87
A can complete a piece of work in 15 days. B is 30% more efficient than A. If they work together, how many days will it take to complete the work?
30.11% of 149.99 + √195.97 ÷ 7.02 = ?
1560.182 ÷ √168 + √143 * √224 – 4649.87 ÷ 30.883= ?
(3/5) of 3025 + (18² + 12²) = ? + 22.22% of 1125