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Fish caught by “i”: a i (2000- (a i + Σ j≠i a j )). Now we have to maximise this expression. Therefore differentiating w.r.t ai and equating to 0 a i = 1000 - Σ j≠i a j /2 Now each player will try to maximise his catch and assuming each one using the same strategy a i = a * to achieve equilibrium a* = 1000 - (n-1) a* /2 a* = 2000 / (n+1) So catch by each player=[2000 / (n+1)] 2
46.2 × 8.4 × 3 + ? = 1200
√361 ÷ (21/23) × 84 = ?
√38809 × √3249 – (91)2 = (?)2 + (50)2 – 36
32.5% of 40 + (13)2 + 102 = ?
(25.111 % of 200) × 26 ÷ 12.99 – 18.88 × 15.82 + 150.33% of 3√ 4917 = ? – 200
...75% of 80 + 12% of 600 + 54 = ?
(√784 ×20+ √4225 ×14)/(√1764 ×5) = ?
72 + 122 - 25% of 600 = ?
140% of 9/8 of ? = 108% of 2800