Question
The mean and median of 100 observations are 50 and 52
respectively, the value of the largest item is 100. Later it was found out that the value 110 was misread as 100. The new corrected mean and median will be?Solution
Mean = 50 Median = 52 N = 100 EX = 5000 EXc = 5000-100+110 = 5010 Correct Mean = 5010 / 100 = 50.1 Value of median will not change as it is positional average.
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