For a frequency distribution if Coefficient of variation is 5, standard deviation is 2 and Karl Pearson’s coefficient of skewness is 0.5, the value of mean and mode are
CV = 5 SD = 2 Sk = 0.5 Also, CV = {SD / Mean} *100 5/100 = 2/Mean Mean = 40 And, Sk = (Mean – Mode) / SD 0.5 = (40 – Mode) / 2 1 = 40 – Mode Mode = 39
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