Question
A dice was rolled 3 times. What is the probability of
getting 5 at least once?Solution
n = 3 p (success) = 1/6 q (failure) = 5/6 P (getting 5 at least once ) = 1 ā P ( not getting 5) P (not getting 5 ) = 5/6 * 5/6 * 5/6 = 125 / 216 (3C0 p0 q3-0) P (getting 5 at least once ) = 1 ā 125 / 216 = 91 / 216
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