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Let X denote the number of tails tossed before the head appears. Then X is a geometric random variable. P(head) = 1 / 2 and the expectation is E(X)=1 / (1/2) = 2.
? = 6.25% of 240 + 252 + 172 – 16 × 17
25639 – 5252 – 3232 = ?
(560 ÷ 32) × (720 ÷ 48) = ?
34 × 2.5 + 6.4 × 1.5 – 4.8 × 1.2 =?
108² + 99 X 98² =?
...[564 + 32 of 18 × 9 ÷ 12 + 162 ] ÷ 4 = ?
?/4 ÷ 9/? = 15% of 800 + `1(2/3)` × `1(1/5)` × 1/2
1(1/2)+ 11(1/3) + 111(1/2) + 1111(1/3) + 11111(1/2) = ?
0.25 x 696 ÷ 0.3 = ?
17.5% of 400 – 24% of 150 = ?