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Let E be the event of getting an even number on one die and an odd number on the other E = {( (1,2) (1,4) (1,6) (2,1) (2,3) (2,5) (3,2) (3,4) (3,6) (4,1) (4,3) (4,5) (5,2) (5,4) (5,6) (6,1) (6,3) (6,5)} So, n (E) = 18 n(E) / n(S) = 18/36 = ½.
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