Which former South African cricketer has been appointed

Statement:A≤M=T<C; T≥F ;C ≥D>E<G

I. C > F

II.E < C

Statements: A > E ≤ B; G < C ≤ E; D < C ≤ F

Conclusions:

I. D < B

II. F ≤ E

III. A > G

Statements: A > I = L ≥ Y = T ≥ W, D < V ≤ W

Conclusions:

I. Y ≥ D

II. V ≤ L

III. I > D

Statements: D = E ≥ G = K, O > B ≤ C = K, E ≤ I < F

Conclusions: I. K > O II. D ≥ C

Statements: L # W, W % V, V $ H, H # T

Conclusions : I. V @ T II. H & W III .V # T

Statements: G < H  ≤  I, V  ≥ W = G, R  ≥ I = A

Conclusions :I. R > G   II. A ≥ H     III. H ≤ R

Statement: X>W=Y>N≤P; W≥Z ;Z ≥P

I. X>Z

II. W≥P

Statement: H > G = M > S; G `>=`  T > L; M `<=`  F <   U

Conclusion:  I. F > S                    II. T < H

Statements:

A ≤ P ≤ Q = M; Y ≥ L > A

Conclusions:

I. P ≤ L

II. L ˃ Y