Question
Train βAβ running with a speed of 108 km/hr crosses
a vertical pole in 8 seconds. Find the approx. time taken by the train βAβ to cross a train βBβ whose length is 130 metres less than that of train βAβ and whose speed is 1/5 more than that of train βAβ if both are running in opposite direction.Solution
Speed of train βAβ = 108 Γ (5/18) = 30 m/sec Length of train βAβ = 30 Γ 8 = 240 metres Length of train βBβ = 390 β 240 = 110 metres Speed of train βBβ = 30 + (30/5) = 36 m/sec Required time taken = (240 + 110)/(30 + 36) = 5.30 = 5 seconds
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