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Interest received from scheme ‘A’ = (7500 × 16 × 3) ÷ 100 = Rs. 3600 Let the rate of simple interest offered by scheme ‘B’ = ‘k%’ p.a. ATQ; (6000 × 2 × k) ÷ 100 = 3600 Or, 120k = 3600 Or, k = (3600/120) = 30 So, rate of simple interest offered by scheme ‘B’ = 30% per annum.
sin2 9 ° + sin2 10 ° + sin2 11 ° + sin2 12 ° + ……… + sin2 81 ° = ?
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If tan θ = (2/√5), then determine the value of cos2 θ
If √3cosec 2x = 2, then the value of x:
If x = (sin 30 ° + cos 30 ° )/sec 60 ° , then find the value of 4x.
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If sin x + cos x = √2 sin x, then the value of sin x - cos x is:
Simplify the given equation: