Question
A work can be completed by βAβ and βBβ, alone in
15 days and 10 days, respectively. Find the number of days taken by βCβ to complete the same work alone if βAβ, βBβ and βCβ together can complete the whole work in 4 days.Solution
Let total work = 30 units (LCM of 15 and 10) Efficiency of βAβ = (30/15) = 2 units/day Efficiency of βBβ = (30/10) = 3 units/day Combined efficiency of βAβ, βBβ and βCβ = (30/4) = 7.5 units/day Efficiency of βCβ = 7.5 β (2 + 3) = 2.5 units/day Required time taken = (30/2.5) = 12 days

Select a suitable figure from the Answer Figures that would replace the question markΒ (?)Β from question figure.
Select the figure which will come next in the following figure series.
Three of the following four figure pairs are alike in a certain way and thus form a group. Which is the one that does not belong to that group?
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A piece of paper is folded and cut as shown below in the question figures from the given answer figures, indicates how it will appear when opened?
<...Select a figure from amongst the Answer Figures.
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Option figures:
Select the figure that can replace the question mark (?) in the following series.