Train ‘A’ can cross a pole in 8 seconds and a 140 metre long platform in 12 seconds. If the ratio of length of train ‘A’ and train ‘B’ is 2:5, respectively, then find the time taken by train ‘B’ to cross a pole with a speed of 25 m/s.
Let the length and speed of the train ‘A’ be ‘l’ metre and ‘s’ m/s, respectively. According to question, l = 8s Also, 12s = 8s + 140 Or, 4s = 140 Or, s = 35 Therefore, length of train ‘A’ = 8s = 280 metres Length of train ‘B’ = 280 × (5/2) = 700 metres Required time taken = 700 ÷ 25 = 28 seconds
I. x³= ((4)5+ (15)³)/(3)4
II. 8y³=(-13)3÷ √1521+ (3y)³
I. x2 + 12√2 x + 22 = 0
II. y2 - 13√2 y – 28 = 0
What is the speed of the stream if a ship takes 15 hours to travel 240 km in calm waters, given that the ratio of its speed against the current to its s...
I. 2y² - 3y – 14 = 0
II. 3x² - 7x + 4 = 0
I. 2x² - 11x + 12 = 0
II. 12y² + 29y + 15 = 0
I. 3x² - 22 x + 40 = 0
II. 4y² + 22y + 24 = 0
I. 3y2 + 13y - 16 = 0
II. 3x2 – 13x + 14 = 0
I. 84x² - 167x - 55 = 0
II. 247y² + 210y + 27 = 0
I. 6x² + 37x + 45 = 0
II. 3y² - 11y + 6 = 0
I.√(3x-17)+ x=15
II. y+ 135/y=24
