Ratio of speeds of ‘A’ and ‘B’ is 4:9, respectively. If they participate in a 360-metre race and ‘B’ gives ‘A’, a head start of ‘m’ metres, then they finish the race at the same time. Find the value of ‘m’.
Let the distance covered by ‘A’ in the time ‘B’ covers 360 metres be ‘x’ metres (x/360) = (4/9) Or, x = 160 So, m = 360– 160 = 200 metres
I. p2 - 19p + 88 = 0Â Â
II. q2 - 48q + 576 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 27x6- 152x3+ 125 = 0
II. 216y6- 91y3+ 8 = 0
I.√(3x-17)+ x=15
II. Â y+ Â 135/y=24Â
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer Â
I. x2 – ...
I. 27x6-152x3+125=0
II. 216y6Â -91y3+8=0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0