πŸ“’ Too many exams? Don’t know which one suits you best? Book Your Free Expert πŸ‘‰ call Now!


    Question

    There is a rectangular paper, whose length and breadth

    are in the ratio 5:2, respectively and it has a perimeter of 70 metres. If a triangular piece with height of 9 metres and base of 14 metres is cut out from the given paper then find the area (in m2) of the remaining paper.
    A 167 Correct Answer Incorrect Answer
    B 177 Correct Answer Incorrect Answer
    C 157 Correct Answer Incorrect Answer
    D 187 Correct Answer Incorrect Answer

    Solution

    Let the length and breadth of the rectangular be β€˜5x’ metres and β€˜2x’ metres, respectively Then, perimeter of the paper = 2 Γ— (length + breadth) = 2 Γ— (5x + 2x) = 14 x metres So, 14x = 70 So, x = (70/14) = 5 So, area of the entire paper = length Γ— breadth = (5 Γ— 5) Γ— (2 Γ— 5) = 25 Γ— 10 = 250 m2 Area of the triangular piece = (1/2) Γ— base Γ— height = (1/2) Γ— 9 Γ— 14 = 63 m2 So, area of the remaining paper = 250 – 63 = 187 m2

    Practice Next

    Relevant for Exams:

    ask-question