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Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 200’ km ATQ, (x/20) = {(x + 200)/30} Or, 30x = 20x + 4000 Or, 10x = 4000 So, x = 400 Total distance between station ‘A’ and station ‘B’ = (400 + 400 + 200) = 1000 km
12 23 65 ? 1239 7409
...1 5 13 25 41 ?
The questions below are based on the given Series-I. The series-I satisfies a certain pattern, follow the same pattern in Series-II and answer the ques...
If 204 196 223 x 284
Then, what is the average of the numbers of the above series?
...6 16 ? 244 1,245 7,506 52,591
...16 9 11 26 ? 912
91 93 97 100 ? 113
351 261 181 111 51 ?
49 121 169 289 361 ?
...1 4 13 46 ? 976
...