Start learning 50% faster. Sign in now
Let, rate of interest be ‘r’% per annum So, 903 = 2800 × {(1 + r/100)2 – 1} 129/400 = {(1 + r/100)2 – 1} 529/400 = (1 + r/100)2 (23/20)2 = (1 + r/100)2 23/20 = 1 + r/100 3/20 = r/100, r = 15 So, simple interest earned = 3200 × 0.15 × 2 = Rs. 960 Required amount = 960 – 903 = Rs. 57
A person invests a sum of money in a bank at a certain rate of interest. The interest earned at the end of the second and third y...
386.99 + 397.99 + ? - 232.02 = 35.02 × 31.99
(23.95)2– (25.006)2+ (8.0099)2– (7.07)2= ? - (14.990)2
√2023.85 + (24.77% of 1999.73) - (3/8 of 799.91) = ?
(115.25 + 324.78) ÷ 4.99 = ?2 – 56.44
17.98% of (16.93 X 8.992 + 46.87) = ? of 14.92 - 26.83 of 1.98
25.13% of 39.89% of 74.78% of 60.21% of ? = 44.89
19.97% of 3/5 ÷ (1 ÷ 74.99) = ?
115.98 + 109.01 + (√575 - 17) X 20.09 - 204.89 + 38.03 = ?