A rectangular piece of copper foil of length 42 cm and

Solution

Width of the rectangular piece of copper foil = 924/42 = 22 cm Since the foil is folded along its width to form a cylinder without any double layer, circumference of the cylinder formed = width of the rectangular foil Also, height of the cylinder so formed = length of the rectangular copper foil So, 2 × π × radius = 22 Radius of cylinder = 22 ÷ (2 × 22/7) = (22/44) × 7 = 3.5 cm So, volume of the cylinder so formed = π × (radius)² × height = (22/7) × 3.5 × 3.5 × 42 = 1617 cm³