Let the length of the edges of the two cubes be ‘a’ cm and ‘b’ cm, respectively According to the question, 6a2 + 6b2 = 1272 Or, a2 + b2 = 1272/6 = 212 And, ab = 98 Using the formula, x2 + y2 = (x – y)2 + 2xy 212 = (a – b)2 + 2 × 98 Or, (a – b)2 = 212 – 196 Or, (a – b)2 = 16 Or, a – b = ±4 So desired difference = 4 cm
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