Question
The time taken by βAβ to build a wall alone is 35%
more than the time taken by him to build it along with βBβ. βBβ will take how much percent more time to build the same wall than the time taken by him to build it along with βAβ?Solution
Let the work βAβ and βBβ, can do in 1 day be βaβ units and βbβ units, respectively. Let they takes βpβ days to build the wall, together Therefore, Total work = (a + b) Γ p units β¦β¦.. (1) According to the question, Time taken by βAβ to build the wall alone = 1.35p days Therefore, total work = 1.35p Γ a unitsβ¦.. (2) From equation (1) and (2), we get 20b/7 = a Therefore, total work to be done = (a + b) Γ p = 27bp/7 units Time taken by 'B' to build the wall = 27bp/7b = 27p/7 days Therefore, required percentage = (27p/7 β p)/p} Γ 100 = 285.71% more time
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