Question
The time taken by ‘A’ to build a wall alone is 35%
more than the time taken by him to build it along with ‘B’. ‘B’ will take how much percent more time to build the same wall than the time taken by him to build it along with ‘A’?Solution
Let the work ‘A’ and ‘B’, can do in 1 day be ‘a’ units and ‘b’ units, respectively. Let they takes ‘p’ days to build the wall, together Therefore, Total work = (a + b) × p units …….. (1) According to the question, Time taken by ‘A’ to build the wall alone = 1.35p days Therefore, total work = 1.35p × a units….. (2) From equation (1) and (2), we get 20b/7 = a Therefore, total work to be done = (a + b) × p = 27bp/7 units Time taken by 'B' to build the wall = 27bp/7b = 27p/7 days Therefore, required percentage = (27p/7 – p)/p} × 100 = 285.71% more time
12 7 10 25 107 ?
...30, 39, 66, ? , 174, 255
 47                         54          ?             74          87          ...
65    69   77 93  ?    189
18 113 559 2247 6721 13451
...219 365 511 ? 803 949
...10Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 8.5Â Â Â Â Â Â Â Â Â Â 16Â Â Â Â Â Â Â Â Â Â Â Â Â ?
...22   39    58    81   ?      141
Complete the series.
19, 23, 26, 30, 33, ?
1240 600 ? 140 90 25
...
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