Question
10 years ago from now, ratio of ages of βRβ and
βLβ was 5:7, respectively. If βLβ is 8 years elder to βRβ, then what will be the age of βLβ, 6 years hence from now?Solution
10 years ago from now,Β (R - 10)/(L-10) = 5/7 Also given; L = R + 8 (R - 10)/(R + 8 -10) = 5/7 (R + 10)/(R - 2) = 5/7 7R - 70 = 5R - 10 2R = 60 R = 60 Present age of βLβ = 30 + 8 = 38 years Age of βLβ, six years hence from now = 38 + 6 = 44 years
40.5 ÷ [4/5 of (32 + 18) - 29/2] = ? ÷ 102
(1/2) β (3/5) + 3(1/3) = ? + (5/6)
(350/?) = 23 + 33
25% of 250 + 32% of 200 = ? Γ· β 16
? = 20% of 1200 + 256
21% of 400 β 150 = ? β 77
172Β - 92Β + 121 - 74 = ?
24% of 150% of 500 + 140 = ? Γ 8Β
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
? = 65% of 40% of (20 Γ 250) β 200