Question
10 years ago from now, ratio of ages of βRβ and
βLβ was 5:7, respectively. If βLβ is 8 years elder to βRβ, then what will be the age of βLβ, 6 years hence from now?Solution
10 years ago from now,Β (R - 10)/(L-10) = 5/7 Also given; L = R + 8 (R - 10)/(R + 8 -10) = 5/7 (R + 10)/(R - 2) = 5/7 7R - 70 = 5R - 10 2R = 60 R = 60 Present age of βLβ = 30 + 8 = 38 years Age of βLβ, six years hence from now = 38 + 6 = 44 years
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