A can complete a work in 25 days. B takes 5 days less than A to complete the same work. In how many days can both of them together complete 90% of the work together?
Time taken by B to complete the work = 25 – 5 = 20 days Let the total work = 100 units Efficiency of A = 100/25 = 4 units/day Efficiency of B = 100/20 = 5 units/day Required time taken = 0.90 x 100/(4+5) = 10 days
