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Let the number of boys and girls be x and (100 - x) respectively. According to the question, Mean = {50x + 40(100 - x)}/100 ⇒ 46 = {50x + 40(100 - x)}/100 ⇒ 4600 = 50x + 4000 - 40x ⇒ 4600 - 4000 = 10x ⇒ x = 600/10 ⇒ x = 60 So, the number of boys is 60. Number of girls = 100 – x = 40 Required difference = 60 – 40 = 20
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