The sum of digits of a two digit number is 10 & difference between its digits is 4.If unit digit is greater than tenth place, what is the number
let number is xy Sum of digit => 10x+y = 10 Difference => y – 10x = 4 => y-4 = 10x Put 10x value and solve we get y =7 and further solve We get => x = 3 So, the required number is 37
