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Let the length of the rod be x metres. According to the question, x – [(x/5) + (x/10) + (x/15) + (x/20) + (x/25) + (x/30)] =24.48 x – [1 – {(60 + 30 + 20 + 15 + 12 + 10)/300}] = 24.48 x – (1 – 147/300) = 12.08 x (300 – 147)/300 = 24.48 x = (24.48 x 300)/153 x = 48m
I. 17x² - 26x – 16 = 0
II. 17y²- 26y + 9 = 0
I. 35 y² + 58 y + 24 = 0
II. 21 x² + 37 x + 12 = 0
I. 18p²- 21p + 6 = 0
II. 16q² - 24q +9 = 0
The equation q2 - 17x + C = 0, has two roots ‘x’ and ‘y’ such that (x – y) = 7. Find an equation which is equal to thrice of the gi...
I. √(17x) + √51 = 0
II. √(4y) + 3 = 0
I. 2 x ² + x – 1 = 0
II. 2 y ² - 3 y + 1 = 0
...I. 2x² + 15 x - 27 = 0
II. 3 y² + 25 y - 18 = 0
I. x2 + 11x + 30 = 0
II. y2 + 17y + 72 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 42x + 392 = 0
Equation 2: y² - 46y + 480 = 0
I). 5p2 - p - 4 = 0
II). q2 - 12q + 27 = 0
