Question
A farmer divides his herd of n cows among his four sons
so that the first son gets one β third the herd, the second son gets one β fifth, the third son gets one β sixth and the fourth son gets 42 cows. The value of n isSolution
According to the question,Β (n/3) + (n/5) + (n/6) + 42 = n (10n + 6n + 5n)/30 + 42 = n 21n/30 + 42 = n 42 = n β (21n/30) 42 = 9n/30 n = (30 x 42)/9 = 140
If p = 50 - q - r and pq + r(q + p) = 816 then find the value of (p2Β + q2Β + r2) .
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