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There is no digit to be 5 on any place in 4 digitsnumber from 1000 to 9999 = 8*9*9*9 (because of at 1000s place 0 and 5 both cannot come so 8 chances like wise for the unit,10s and100s place 5 cannot come so chance will be 9) =5832 Total number between 999 and 10000 = 9000 So, required numbers are =9000–5832=3168
When evaluating an argument, what does it mean to "beg the question"?
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Arguments:
I. Yes, Obesity like other diseases impairs the normal functioning of the body.
...
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I. No, the...
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I. Yes, because through the internet students can h...
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Arguments:
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Argument:
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Argument I: Yes, the state governments are unable to recove...
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Argument I: No, it won’t...
