Four different toys are to be distributed among two children such that each child gets at least one toy. In how many different ways can this be done?
There are 4 toys to be distributed among 2 children such that each child gets at least 1 toy. Required ways = 4C1*3C3 + 4C2*2C2 + 4C3*1C1 = 4 + 6 + 4 = 14 ways.
I. 6x2 + 19x + 10 = 0
II. y2 + 10y + 25 = 0
I. 9x2 + 45x + 26 = 0
II. 7y2 – 59y − 36 = 0
I. 99x² + 161 x + 26 = 0
II. 26 y² + 161 y + 99 = 0
I. 6x² - 13 x + 6 = 0
II. 15 y² + 11 y - 12 = 0
I. 2x2 – 5x - 12 = 0
II. y2 – 11y + 30 = 0
I. 18p²- 21p + 6 = 0
II. 16q² - 24q +9 = 0
I. 4x² - 21x + 20 = 0
II. 8y² - 22y + 15 = 0
I. x² - (16)2 = 0
II. 2y - 14 = 0
I. x2 + 12√2 x + 22 = 0
II. y2 - 13√2 y – 28 = 0
I. 2 x ² + x – 1 = 0
II. 2 y ² - 3 y + 1 = 0
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