A person and his wife appear in the interview for the two vacancies of a post. The probability of the selection of the husband and that of the wife are 1/7 and 1/5 respectively. What is the probability that only one of them will be selected?
Probability of selection of husband = 1/7, it means of not selecting = 6/7 Probability of selection of wife = 1/5, it means of not selecting = 4/5 So, only 1 will be selected = “Wife selected, and husband is not selected” or “husband selected and wife doesn’t” = (1/5)* (6/7) + (1/7)* (4/5) = 6/35 + 4/35 = 10/35 = 2/7
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