New Click Here to Play Diwali Spin and Win and Get Huge Discounts

    Register

    Question

    The length of a rectangle is reduced by 20% and breadth is kept constant, and the new figure that is formed is a square.

    Consider the following statements:

    1. The area of the square is 25% less than the area of rectangle.

    2. The perimeter of square is approximately 11% less than the perimeter of rectangle.

    3. The diagonal of square is approximately 12% less than the diagonal of rectangle.

    Which of the statements given. above is/are correct?

    A 1 only Correct Answer Incorrect Answer
    B 1 and 2 Correct Answer Incorrect Answer
    C 1, 2 and 3 Correct Answer Incorrect Answer
    D 2 and 3 Correct Answer Incorrect Answer

    Solution

    Let length of the rectangle = L, breadth of the rectangle = B Area= L*B Now, length reduced by 20%. So, now length – (4/5)L Breadth remains same So, new figure is square. So, (4/5)L = B So, New area = (4/5)L*B 1.  Difference in area = [{L/B – (4/5) L*B}/ L*B]*100 = 20% (So, wrong as given in the statement 1 to be 25%) 2.   Perimeter of square = 2(4/5) L + 2B = (8/5) L + 2B Perimeter of rectangle = 2(L + B) Difference = [{2L + 2B – (8/5)L – 2B}/ (2(L + B)]*100 = [(2/5)L/ 2(L + (4/5)L]*100 = 11.11% (So, right it is approx. 11%) 3.  Diagonal of rectangle = √(L2 + B2) = √(L2 + (4/5 L)2  = (L/5)*√41 Diagonal of square =side*√2 = (4/5)L*√2 Require   %age   =  [{(√41 - 4√2)*(L/5)}/(L/5)*√41]*100 = 11.65% (So, right it is approx. 12%) Hence option D.

    Practice Next

    Relevant for Exams: