Question
A and B are travelling towards each other with a speed
of 20 km/hr and 30 km/hr. They started at same time and A covered 40 km less distance than B before meeting B. Find the distance between them before starting.Solution
Here time taken by both A and B is same, so the ratio of the distance covered by them will be equal to the ratio of their speeds. Therefore, ratio of the distance covered by A and B = 20:30 = 2:3 Let the distance covered by A and B be 2x km and 3x km respectively. According to question, => 3x – 2x = 40 => x = 40 Therefore, distance between them before starting = 3x + 2x = 5x = 200 km
I. 2x2 - 9 x + 9 = 0Â
II. 2y2 - 7 y + 3 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 2x² - 15x  + 13 = 0
II. 3y² - 6y + 3 = 0
I. x²= 961Â
II. y= √961
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and β, then
I. 27x6-152x3+125=0
II. 216y6Â -91y3+8=0
I. 4x² - 21x + 20 = 0
II. 8y² - 22y + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
I. 3p² + 13p + 14 = 0
II. 8q² + 26q + 21 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
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