Two vehicles A and B travel with uniform speed 30 km per hour and 60 km per hour respectively in the same direction. They start at the same time and from the same place for a distance of 120 km. The faster vehicle B reaches the destination and travels back with the same speed. Assume that the loss of time to change the direction is negligible. If x is the distance travelled by the slower vehicle A before the two vehicles cross each other, then x is
Total distance covered by both vehicles until they meet each other = 2 × 120 = 240 km Total distance covered by both vehicles in 1 hour = 30 + 60 = 90 km Let both vehicles meet each other after x hrs According to the question 90 = 240/x ⇒ x = 240/90 ⇒ x = 8/3 hrs ∴ Distance covered by slower vehicles in 8/3 hrs = 8/3 × 30 = 80 km.
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