If the radius of the new spherical container is double the radius of the old spherical container, then the ratio of the volume of the new container and the volume of the old container is
Let the radius of old spherical container be 1 cm Radius of new spherical container = 2 cm Volume of old spherical container = (4/3) π × 13 = (4/3) π × 1 Volume of new spherical container = (4/3) π × 23 = (4/3) π × 8 ∴ Required ratio = (4/3) π × 8 : (4/3) π × 1 = 8 : 1
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