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Radius (r) of given cylindrical wooden block = 3/2 cm (because Diameter = 2*radius) Length (h) = 20cm The volume of the block = πr²h = π *(3/2)²* (20) = 45 π Now we need to find max number of pieces of 1 cm in diameter. So, radius = 1/2 cm, length = 20cm So, volume of the required block = πr2h = π*(1/2)2*(20) = 5π So, max pieces = 45 π /5 π = 9 pieces.
(23.99)2– (17.99)2+ (1378.88 + 44.88) ÷ ? = 607.998
8.992 + (5.01 × 4.98) + ? = 224.03
14.12 × 21.98 + 25.22% of 195.99 = ? × 50.9
? = 49.99² ÷ (1.98⁵ + 8.01 × 89.91) + 75.15% of (263.89 × 49.11)
10.10% of 999.99 + 14.14 × 21.21 - 250.25 = ?
960.11 ÷ 23.98 × 5.14 – 177.9 = √?
? = 65.78² ÷ (5.01⁵ + 7.02 × 33.33) + 33.33% of (290.88 × 23.09)
? = 49.97% of 38.09% of 1998.95