Question
Three containers have their volumes in the ratio 3: 4:
5. They are full of mixtures of milk and water. The mixtures contain milk and water in the ratio of 4:1, 3:1 and 5:2 respectively. The contents of all these three containers are poured into a fourth container. The ratio of milk and water in the fourth container isSolution
Let the volumes be 3x,4x, and 5x respectively. Container with volume 3x: Milk = (4/4+1)*3x = 12x/5 Water = (1/4+1)*3x = 3x/5 Â Container with volume 4x: Milk (3/3+1) *4x= 12x/4 Water = (1/3+1) *4x = 4x/4 Â Container with volume 5x: Milk (5/5+2) *5x = 25x/7 Water = (2/5+2) *5x = 10x/7 Â Total milk = 12x/5+ 12x/4 + 25x/7 = 314x/35 Â Total water = 3x/5+ 4x/4 + 10x/7 = 106x/35 Â The ratio of milk to water in the 4th container = 314x/35: 106x/35 =157:53
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