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Total number of outcome is 6*6 = 36. Now, according to the question we need the product of numbers on two dice to be even. We know “odd* even = even” as well as “even*even = even" But odd*odd = odd. So, the possibility of the odd number on the first dice is 3 (1, 3, 5) and similarly for 2nd dice. So, the number of outcomes when the product will be odd = 3*3 = 9 ways. So, required probability =36-9/36 = 27/36 = 3/4
Statements: B ≥ U > P = E ≥ X; X > K > N ≥ J
Conclusions: I. N < P II. J ≤ X
Statements: M ≤ N; O < R; O = N; S ≥ Q; N > S
Conclusions:
(i) Q < M
(ii) N ≥ Q
(iii) M > R
...Statements:
C > D ≥ E ≤ F; Y ≥ Z ≥ A = C
Conclusion:
I. Y > F
II. F ≥ Y
Statements: E > F = G; H < I = F; J > I
Conclusions: I) J > G
II) E < J
III) H > E
Statements: H > S ≥ F = B ≤ U≤ T; E ≤ K ≤ B
Conclusions:I. U ≥ E II. S > T
Statements: A > B ≤ D; G < C ≤ B; F < C ≤ E
Conclusions:
I. F < D
II. E ≤ B
III. A > G
Statements: Q ≤ B = S < U > M ≥ Z
Conclusion: I. U > Q II. S ≤ Z
...Statements: L ≤ Y = T ≤ S; S = F ≤ U; K > N = U
Conclusions:
I. K > T
II. U ≥ L
...In which of these expression ‘J > B’ is definitely True?
Statements:
Only Ear is Eye.
No Hand is Ear.
Only a few Hands are Legs.
Conclusion:
I. Some Eyes can be Legs.
...
