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    Question

    14 years ago, the age of a father was three times the

    age of his son. Now, the father is twice as old as his son. What is the sum of the present ages of the father and the son?
    A 84 years Correct Answer Incorrect Answer
    B 56 years Correct Answer Incorrect Answer
    C 42 years Correct Answer Incorrect Answer
    D 98 years Correct Answer Incorrect Answer

    Solution

    ATQ, Let the son's present age = x, and the father's present age = y. 14 years ago: Father = 3 ├Ч Son = yтИТ14 = 3(xтИТ14) тЯ╣ y = 3xтИТ28 Now: Father = 2 ├Ч Son = y = 2x On Solving we get: From y=2x and y=3xтИТ28: 2x=3xтИТ28тЯ╣x=28 y=2x=56. Sum of ages = x + y = 28+56 = 84 years

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