Question
Train 'X' is moving at a speed of 108 km/h and takes 12
seconds to completely pass train 'Y', which is traveling in the opposite direction at 162 km/h. Additionally, train 'Y' is 180 meters longer than train 'X'. Determine the time required for the longer train to pass a stationary tree.Solution
ATQ,
Let the length of shorter train (train ‘X’) be ‘x’ meter. So, length of the longer train (train ‘Y’) = (x + 180) meters ATQ; {(162 + 108) × (5/18)} = {(x + x + 180)/12} Or, (75 × 12) = (2x + 180) Or, (900 – 180) = 2x Or, (720/2) = x So, x = 360 m Length of shorter train (train ‘X’) = 360 m Length of longer train (train ‘Y’) = 540 m So, time taken by the longer train to cross a tree = {540/(162 × 5/18)} = (540/45) = 12 secondsÂ
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555, 430, ?, -320, -1320, -3320Â
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