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ATQ,
Let the length of shorter train (train ‘X’) be ‘x’ meter. So, length of the longer train (train ‘Y’) = (x + 180) meters ATQ; {(162 + 108) × (5/18)} = {(x + x + 180)/12} Or, (75 × 12) = (2x + 180) Or, (900 – 180) = 2x Or, (720/2) = x So, x = 360 m Length of shorter train (train ‘X’) = 360 m Length of longer train (train ‘Y’) = 540 m So, time taken by the longer train to cross a tree = {540/(162 × 5/18)} = (540/45) = 12 seconds