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ATQ, Given: Area = 30 cm² → l×b=30 Perimeter = 26 cm → 2(l+b)=26 → l+b=13 Express b in terms of b=13−l Substitute in the Area Formula l×(13−l)=30 l² −13l+30=0 Solve for I (l−10)(l−3)=0 So, l=10 or l=3. Since length is greater than breadth, length = 10 cm.
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