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    Question

    A 200 kg mixture of gold and silver contains 40% gold.

    Find the amount of silver that must be added to the mixture so that gold becomes 1/7th of the remaining mixture.
    A 360 kg Correct Answer Incorrect Answer
    B 335 kg Correct Answer Incorrect Answer
    C 320 kg Correct Answer Incorrect Answer
    D 225 kg Correct Answer Incorrect Answer

    Solution

    ATQ, Initial quantity of gold in 200 kg mixture = 0.40×200=80 kg Initial quantity of silver in 200 kg mixture = 200−80=120 kg Let 'z' kg of silver be added to the mixture. Thus, the fraction of gold in the new mixture becomes: 360 kg of silver must be added.

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