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ATQ; A = 14C And, A = (7/3) × B So, 14C = (7/3) × B Or, 6C = B Since, A + B + C = 360 So, 14C + 6C + C = 360 Or, 21C = 360 Or, C = 120/7 A = (120/7) × 14 = 240 And, B = 6 × (120/7) = 720/7 Required value = 10 × (120/7) – (720/7) = 480/7
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