Question
In August 2020, Narendra Singh Tomar has launched the
Integration of ICAR-IIHR Seed Portal with YONO Krishi Web Application of:Solution
The correct answer is A
More Previous Year Paper Questions
345 = √2704 ÷ (?% of 104) + 7 3
- Find the simplified value of following expression:
0.998 + 0.882 + 0.12 {(81% of 800 + 28 × 4) – 27 × ?} = 11 × 20
(54/6) × 5 + 12 × (17/2) = ?% of 700
Solve: 3/4÷2/3 ​
[5 X {(52 X 5) - 10} + 50 of 20] = ?
22 * 6 + 45% of 90 + 65% of 180 = ?
[192 ÷ 6 × 5] ÷ (? + 3) = 20Â
[(1245 ÷ 9) ÷ 12] × 540 = ?2 – 175
1555.5 + 1000.8 – 1354.3 = ? + 52
Relevant for Exams:
