Question
The difference of simple interest from two banks on Rs.
8,000 in 3 years is Rs. 800. If the rate of interest per annum in two banks is R1 and R2, then what is the value of R1- R2? (Where R1 > R2)Solution
SI= 800 P= 8000, T =3y r = R 1 -R 1 [8000×3×(R 1 -R 2 )]/100 = 800 R 1 -R 2 = 10/3%
16 of 25 - 12 of 15 = ? of 5 of 11Â
18/2 of 3/9 of 2/6 of 69690= ?
Find the value of 16 x [(8 - 5) of 12 ÷ 4].
520% of 360 – 12% of 400 = ? x 4
If 840 ÷ 12 + 1025 ÷ 25 - n + 45 × 4 = 960 ÷ 16 × 132 ÷ 44, then the value of n is:
22% of 280 + 34% of 1080 × 5/12 =? + 16% of 460
1*1/2 + 11*1/3 + 111*1/2 + 1111*1/3 + 11111*1/3 =?
Simplify the following expressions and choose the correct option.
(45% of 640) ÷ 8 + (3/4 of 96) = ?
458.32-563.32+659.32=?
62 + 43 + 625(1/4) - ? = 102