Question
The value of [(3√2+2) × (3√2-2)] of 13
+ 20 is:Solution
Formula used: (a - b)(a + b) = a2 - b2 = [(3√2 + 2) × (3√2 - 2)] of 13 + 20 [(3√2)2 - (2)2] × 13 + 20 [18 - 4] × 13 + 20 14 × 13 + 20 202 ∴ The required result = 202
Three series are provided below. You need to determine the values of A, B, and C and subsequently establish a relationship among them.
I: 4, 10...
There are three series given below which are following with the same pattern.
Series I: 1, 12, 38, 193, 1355
Series II: 6, B, C, D, E
...6 6 13 39 ? 226
...If 14, 32, x, 50, -13, 86,
then, find the value of (10x + 5x – 20)?
...18, 32, 50, 82, 132, ?
Direction: Which of the following will replace ‘?’ in the given question?
342, ‘?’, 420, 462, 506, 552, 60
11 28 47 70 ? 130
...231 451 671 242 485 264
...21 11.5 13 ? 45.5 116.75
...18, 25, 33, 42, 52, 63, ?
